Help with gain calculation - MoreDat2024-03-29T00:00:35Zhttp://moredat.ning.com/forum/topics/help-with-gain-calculation?commentId=6483656%3AComment%3A1968&feed=yes&xn_auth=noI think the best way to answe…tag:moredat.ning.com,2012-06-04:6483656:Comment:19682012-06-04T00:02:04.423ZJerryhttp://moredat.ning.com/profile/Jerry
<p>I think the best way to answer your question is to try an example. Let’s calculate the gain using all 3 of the voltage types that you mentioned. The first one will be arbitrary numbers. The other two will be based off the first one.</p>
<p>For RMS let’s arbitrarily assume that we have 10 volts out and 1 volt in. That would make our gain = Vout/Vin = 10/1 = 10. So we have a <b>gain of 10.</b></p>
<p>Now for peak voltage we need to take our RMS voltages and convert them. To convert the…</p>
<p>I think the best way to answer your question is to try an example. Let’s calculate the gain using all 3 of the voltage types that you mentioned. The first one will be arbitrary numbers. The other two will be based off the first one.</p>
<p>For RMS let’s arbitrarily assume that we have 10 volts out and 1 volt in. That would make our gain = Vout/Vin = 10/1 = 10. So we have a <b>gain of 10.</b></p>
<p>Now for peak voltage we need to take our RMS voltages and convert them. To convert the 10 volts RMS we would have Vpeak = (Vrms)(1.414) = (10)(1.414) = 14.14Vpeak. To convert the 1 volt RMS we would have Vpeak = (Vrms)(1.414) = (1)(1.414) = 1.414Vpeak. Now to calculate our gain using peak voltages we would have Vout/Vin = 14.14/1.414 = 10. So we have a <b>gain of 10.</b></p>
<p>Now let’s try peak-to-peak voltages. We will need to convert our peak voltages to peak-to-peak. To convert the 14.14Vpeak we would have Vpp = (Vp)(2) = (14.14)(2) = 28.28Vpp. To convert the 1.414Vpeak we would have Vpp = (Vp)(2) = (1.414)(2) = 2.828Vpp. Now to calculate our gain using peak-to-peak voltages we would have Vout/Vin = 28.28/2.828 = 10. So we have a <b>gain of 10.</b></p>
<p>So as long as you use the same kind of voltage for both the output and the input, the gain will come out the same.</p>