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Why does a transformer supposedly burn out when supplied with DC? I did do some searching and found explanations relating to emf as e=d(flux)/dt., i.e. change in flux for emf. Change in flux didn't happen in DC ...but what makes that the reason for transformer not to burn(or wear out) in AC, whereas wear out in DC?? Is it because all the current is drawn into primary itself in a DC and whereas part of the current component does work to link flux in secondary(in case of AC) ? - Is my understanding right?

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